Toán Lớp 11: Giải Phương trình
tanx(1-2sin^2x)=0
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Toán Lớp 11: Giải Phương trình
tanx(1-2sin^2x)=0
Comments ( 1 )
$x = \frac{\pi }{4} + \frac{{k\pi }}{2} $
\tan x = 0\\
1 – 2{\sin ^2}\left( {2x} \right) = 0
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = k\pi \\
\cos \left( {2x} \right) = 0
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = k\pi \\
x = \frac{\pi }{4} + \frac{{k\pi }}{2}
\end{array} \right.\]