Toán Lớp 11: Giải phương trình sau
Sin2x = sinx
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Toán Lớp 11: Giải phương trình sau
Sin2x = sinx
Comments ( 2 )
\sin 2x = \sin x\\
\Leftrightarrow \left[ \begin{array}{l}
2x = x + k2\pi \\
2x = \pi – x + k2\pi
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = k2\pi \\
x = \dfrac{\pi }{3} + \dfrac{{k2\pi }}{3}
\end{array} \right.\left( {k \in \mathbb{Z}} \right)
\end{array}$