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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: Giúp e vssss: cho hình bình hành ABCD. CMR: AC bình + BD bình= 2(AB bình + AD bình)

Toán Lớp 10: Giúp e vssss: cho hình bình hành ABCD. CMR: AC bình + BD bình= 2(AB bình + AD bình)

Comments ( 1 )

  1. \qquad ABCD là hình bình hành 
    =>BC=AD;\vec{BC}=\vec{AD}
    \qquad \vec{AB}+\vec{AD}=\vec{AC}
    \qquad \vec{BA}+\vec{BC}=\vec{BD}
    Ta có:
    \qquad AC^2+BD^2
    =(\vec{AC})^2+(\vec{BD})^2
    =(\vec{AB}+\vec{AD})^2+(\vec{BA}+\vec{BC})^2
    =(\vec{AB})^2+2\vec{AB}.\vec{AD}+(\vec{AD})^2+(\vec{BA})^2+2.\vec{BA}.\vec{BC}+(\vec{BC})^2
    =AB^2+AD^2+BA^2+BC^2+2\vec{AB}.\vec{BC}+2\vec{BA}.\vec{BC}
    =2AB^2+AD^2+AD^2+2\vec{BC}.(\vec{AB}+\vec{BA})
    =2(AB^2+AD^2)+2.\vec{BC}.\vec{0}
    =2(AB^2+AD^2)+\vec{0}
    =2(AB^2+AD^2)
    Vậy: AC^2+BD^2=2(AB^2+AD^2) (đpcm)

    toan-lop-10-giup-e-vssss-cho-hinh-binh-hanh-abcd-cmr-ac-binh-bd-binh-2-ab-binh-ad-binh

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222-9+11+12:2*14+14 = ? ( )