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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: cho A= {x €R/1:|x-2|>2} và B={x €R/|x-1|<1} hãy tìm A giao B , A hợp B

Tháng Hai 6, 2023 Toán học 1 Comment 0 views

Toán Lớp 10: cho A= {x €R/1:|x-2|>2} và B={x €R/|x-1|<1} hãy tìm A giao B , A hợp B

Comments ( 1 )

  1. maingocquynhnhu2k1
    maingocquynhnhu2k1
    6 Tháng Hai, 2023 at 7:37 sáng
    Reply
    $\begin{array}{*{20}{l}} {A = \left\{ {x \in R|\dfrac{1}{{\left| {x – 1} \right|}} > 2} \right\}}\\ {{\rm{ \;}} + \dfrac{1}{{\left| {x – 2} \right|}} > 2 \Leftrightarrow \left| {x – 2} \right| < \dfrac{1}{2}}\\ {{\rm{ \;}} \Leftrightarrow {\rm{ \;}} – \dfrac{1}{2} < x – 2 < \dfrac{1}{2}}\\ {{\rm{ \;}} \Leftrightarrow \dfrac{3}{2} < x < \dfrac{5}{2}}\\ {{\rm{ \;}} \Rightarrow A = \left( {\dfrac{3}{2};\dfrac{5}{2}} \right)}\\ {B = \left\{ {x \in R|\left| {x – 1} \right| < 1} \right\}}\\ {{\rm{ \;}} + \left| {x – 1} \right| < 1 \Leftrightarrow {\rm{ \;}} – 1 < x – 1 < 1 \Leftrightarrow 0 < x < 2}\\ {{\rm{ \;}} \Rightarrow B = \left( {0;2} \right)}\\ { \Rightarrow A \cap B = A = \left( {\dfrac{3}{2};2} \right)}\\ {{\rm{ \;}} \Rightarrow A \cup B = \left( {0;\dfrac{3}{2}} \right] \cup \left( {\dfrac{3}{2};\dfrac{5}{2}} \right)} \end{array}$ 

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222-9+11+12:2*14+14 = ? ( )

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