Toán Lớp 6: (2x+8).(3-x)=0 giúp mik với chi tiết nha
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Toán Lớp 6: (2x+8).(3-x)=0 giúp mik với chi tiết nha
Comments ( 2 )
(3-x)=0 ; (2x+8)=0
=> -x=-3 => 2x=-8
=> x=3 => x=-8/2
=> x=3 => x=-4
Vậy x∈{3;-4}
(2x+8).(3-x)=0
Ta có :
2x+8 = 0
2x = 0 – 8
2x = -8
x =( -8 ) : 2
x = -4
3-x=0
x = 3 – 0
x = 3
=> x $\in$ { -4 ; 3 }