Toán Lớp 8: Tìm n thuộc Z để 2n^2+5n-1 chia hết cho 2n-1
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Toán Lớp 8: Tìm n thuộc Z để 2n^2+5n-1 chia hết cho 2n-1
Comments ( 2 )
2n^2+5n-1 vdots 2n-1
⇔4n^2+10n-2vdots2n-1
⇔(4n^2-1)+(10n-5)+4vdots2n-1
⇔4 vdots 2n-1
⇔2n-1inƯ(4)={pm1;pm2;pm4}
⇔n={0;1}
Bn xem hình
