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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: 1.sin x =1/2 2.sin(x+30 độ)=1/2 3.sin2x =căn2 /2

Toán Lớp 11: 1.sin x =1/2
2.sin(x+30 độ)=1/2
3.sin2x =căn2 /2

Comments ( 1 )

  1. Giải đáp:
    \(\begin{array}{l}
    1,\\
    \left[ \begin{array}{l}
    x = \dfrac{\pi }{6} + k2\pi \\
    x = \dfrac{{5\pi }}{6} + k2\pi 
    \end{array} \right.\,\,\,\left( {k \in Z} \right)\\
    2,\\
    \left[ \begin{array}{l}
    x = k.360^\circ \\
    x = 120^\circ  + k.360^\circ 
    \end{array} \right.\,\,\,\left( {k \in Z} \right)\\
    3,\\
    \left[ \begin{array}{l}
    x = \dfrac{\pi }{8} + k\pi \\
    x = \dfrac{{3\pi }}{8} + k\pi 
    \end{array} \right.\,\,\,\,\left( {k \in Z} \right)
    \end{array}\)
    Lời giải và giải thích chi tiết:
     Ta có:
    \(\begin{array}{l}
    1,\\
    \sin x = \dfrac{1}{2}\\
     \Leftrightarrow \sin x = \sin \dfrac{\pi }{6}\\
     \Leftrightarrow \left[ \begin{array}{l}
    x = \dfrac{\pi }{6} + k2\pi \\
    x = \pi  – \dfrac{\pi }{6} + k2\pi 
    \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
    x = \dfrac{\pi }{6} + k2\pi \\
    x = \dfrac{{5\pi }}{6} + k2\pi 
    \end{array} \right.\,\,\,\left( {k \in Z} \right)\\
    2,\\
    \sin \left( {x + 30^\circ } \right) = \dfrac{1}{2}\\
     \Leftrightarrow \sin \left( {x + 30^\circ } \right) = \sin 30^\circ \\
     \Leftrightarrow \left[ \begin{array}{l}
    x + 30^\circ  = 30^\circ  + k.360^\circ \\
    x + 30^\circ  = 180^\circ  – 30^\circ  + k.360^\circ 
    \end{array} \right.\\
     \Leftrightarrow \left[ \begin{array}{l}
    x = k.360^\circ \\
    x = 120^\circ  + k.360^\circ 
    \end{array} \right.\,\,\,\left( {k \in Z} \right)\\
    3,\\
    \sin 2x = \dfrac{{\sqrt 2 }}{2}\\
     \Leftrightarrow \sin 2x = \sin \dfrac{\pi }{4}\\
     \Leftrightarrow \left[ \begin{array}{l}
    2x = \dfrac{\pi }{4} + k2\pi \\
    2x = \pi  – \dfrac{\pi }{4} + k2\pi 
    \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
    2x = \dfrac{\pi }{4} + k2\pi \\
    2x = \dfrac{{3\pi }}{4} + k2\pi 
    \end{array} \right.\\
     \Leftrightarrow \left[ \begin{array}{l}
    x = \dfrac{\pi }{8} + k\pi \\
    x = \dfrac{{3\pi }}{8} + k\pi 
    \end{array} \right.\,\,\,\,\left( {k \in Z} \right)
    \end{array}\)

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222-9+11+12:2*14+14 = ? ( )

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