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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: thực hiện phép tính $\frac{1}{\sqrt{3-2}}$ $+$ $\frac{1}{\sqrt{3}+2}$

Toán Lớp 9: thực hiện phép tính
$\frac{1}{\sqrt{3-2}}$ $+$ $\frac{1}{\sqrt{3}+2}$

Comments ( 2 )

  1. \frac{1}{\sqrt{3}-2}+\frac{1}{\sqrt{3}+2}
    =\frac{\sqrt{3}+2+\sqrt{3}-2}{(\sqrt{3}-2)(\sqrt{3}+2)}
    =\frac{2\sqrt{3}}{3-4}
    =-2\sqrt{3}
    @Nobitao@

  2. $ \dfrac{1}{\sqrt[]{3} – 2 } + \dfrac{1}{\sqrt[]{3} + 2 }$
    $ = \dfrac{ \sqrt[]{3} + 2 + \sqrt[]{3} – 2 }{ ( \sqrt[]{3} -2 ) ( \sqrt[]{3} + 2 ) } $
    $ = \dfrac{2\sqrt[]{3}}{3-4} $
    $ = \dfrac{2\sqrt[]{3}}{-1} $
    $ = – 2\sqrt[]{3} $
     

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222-9+11+12:2*14+14 = ? ( )