Toán Lớp 8: (x+4)^2-(x-2)(x+2)
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Toán Lớp 8: (x+4)^2-(x-2)(x+2)
giúp mik đi;-;
Comments ( 2 )
Giải đáp:
$(x+4)^2-(x-2).(x+2)$
$= x^2+8x+16-x²+4$
$= (x^2-x^2)+8x+(16+4)$
$= 8x+20$
(x+4)²-(x-2)(x+2)= x²+8x+16-x²+4=8x+20