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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Bài 1: phân tích đa thức sau thành nhân tử: a) 5×3 – 45x b) a3 – 8 + 6a2 -12a c) ( a + b )3 + ( a – b )3 d) x ( 2x – 7 ) ( 4x – 14 ) e

Toán Lớp 8: Bài 1: phân tích đa thức sau thành nhân tử:
a) 5×3 – 45x
b) a3 – 8 + 6a2 -12a
c) ( a + b )3 + ( a – b )3
d) x ( 2x – 7 ) ( 4x – 14 )
e) x4 + 3×3 – 9x – 9
Bài 2: tìm x:
a) 2×3 – 50x =0
b) x3 – 16x = 0
c) 7x ( x – 2004 ) – x + 2004 = 0
d) 5x ( x – 3 ) + 7 ( x + 3 ) = 0

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    Bài 1:
    a) 5x³-45x
    =5x(x²-9)
    =5x(x-3)(x+3)
    b) a³-8+6a²-12a
    =(a-2)(a²+2a+b²)+6a(a-2)
    =(a-2)(a²+8a+b²)
    c) (a+b)³+(a-b)³ =a³+3a²b+3ab²+b³+a³-3a²b+3ab²-b³
    =2a³+6ab²
    =2a²(a+3b²)
    d)x ( 2x – 7 )( 4x – 14 )
    Sửa đề:
    x ( 2x – 7 )+ ( 4x – 14 )
    =x ( 2x – 7 )+2(2x-7)
    =(2x-7)(x+2)
    e)x^4+3x³-9x-9
    =x^4-3²+3x(x²-3)
    =(x²-3)(x²+3)+3x(x²-3)
    =(x²-3)(x²+3x+3)
    Bài 2:
    a)2x³-50x=0
    ⇔2x(x²-25)=0
    ⇔2x(x-5)(x+5)=0
    =>\(\left[ \begin{array}{l}2x=0\\x-5=0\\x+5=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=0\\x=5\\x=-5\end{array} \right.\)
    b)x³-16x=0
    ⇔x(x²-16)=0
    ⇔x(x-4)(x+4)=0
    =>\(\left[ \begin{array}{l}x=0\\x-4=0\\x+4=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=0\\x=4\\x=-4\end{array} \right.\)
    c)7x ( x – 2004 ) – x + 2004 = 0
    ⇔7x(x-2004)-(x-2004)=0  
    ⇔(7x-1)(x-2004)=0
    =>\(\left[ \begin{array}{l}7x-1=0\\x-2004=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=\dfrac{1}{7}\\x=2004\end{array} \right.\)
    d)5x ( x – 3 ) + 7x ( x + 3 ) = 0
    ⇔5x²-15x+7x²+21x=0
    ⇔12x²+6x=0
    ⇔6x(2x+1)=0
    =>\(\left[ \begin{array}{l}6x=0\\2x+1=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=0\\x=\dfrac{-1}{2}\end{array} \right.\)

  2. 1.
    a) 5x³-45x
    =5x(x²-9)=5x(x-3)(x+3)
    b) a³-8+6a²-12a=(a-2)(a²+2a+b²)+6a(a-2)
    =(a-2)(a²+8a+b²)
    c) (a+b)³+(a-b)³=a³+3a²b+3ab²+b³+a³-3a²b+3ab²-b³
    =2a³+6ab²=2a²(a+3b²)
    d) x ( 2x – 7 ) ( 4x – 14 )???
    e)x^4+3x³-9x-9
     =x^4-3²+3x(x²-3)=(x²-3)(x²+3)+3x(x²-3)
    =(x²-3)(x²+3x+3)
    Bài 2
    a)2x³-50x=0
    ⇔2x(x²-25)=0
    ⇔2x(x-5)(x+5)=0
    ⇔2x=0⇔x=0
        x-5=0⇔x=5
        x+5=0⇔x=-5
    b)x³-16x=0
    ⇔x(x²-16)=0
    ⇔x(x-4)(x+4)=0
    ⇔x=0
        x-4=0⇔x=4
        x+4=0⇔x=-4
    c)7x ( x – 2004 ) – x + 2004 = 0
    ⇔7x(x-2004)-(x-2004)=0
      ⇔(7x-1)(x-2004)=0
      ⇔x=1/7
          x=2004
    d)5x ( x – 3 ) + 7x ( x + 3 ) = 0
    ⇔5x²-15x+7x²+21x=0
    ⇔12x²+6x=0
    ⇔6x(2x+1)=0
    ⇔x=0
        x=-1/2

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222-9+11+12:2*14+14 = ? ( )

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