Toán Lớp 6: tìm x bt ( dạng 2)
a. . |3-2x| -|x-1/2|=0
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Toán Lớp 6: tìm x bt ( dạng 2)
a. . |3-2x| -|x-1/2|=0
Comments ( 2 )
|3-2x|=|x-1/2|
=>\(\left[ \begin{array}{l}3-2x=0\\x-\dfrac{1}{2}=0\end{array} \right.\)
=>\(\left[ \begin{array}{l}2x=3\\x=\dfrac{1}{2}\end{array} \right.\)
=>\(\left[ \begin{array}{l}x=\dfrac{3}{2}\\x=\dfrac{1}{2}\end{array} \right.\)
Vậy x in{3/2;1/2}