Toán Lớp 7: Tìm x biết $2021^{x+1}$ +$2021^{x}$ =2022
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Toán Lớp 7: Tìm x biết $2021^{x+1}$ +$2021^{x}$ =2022
Comments ( 2 )
2021^x. 2021+2021^x.1=2022
2021^x(2021+1)=2022
2021^x.2022=2022
2021^x=2022:2022
2021^x=1
2021^x=2021^0
=>x=0
Vậy x=0