Toán Lớp 8: giải phương trình x^2+100-3000=0
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Toán Lớp 8: giải phương trình x^2+100-3000=0
Comments ( 2 )
x^2+100-3000=0
<=>x^2-2900=0
<=>x^2=2900
<=>\(\left[ \begin{array}{l}x=\sqrt{2900}\\x=-\sqrt{2900}\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=\sqrt{29.100}\\x=-\sqrt{29.100}\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=10\sqrt{29}\\x=-10\sqrt{29}\end{array} \right.\)
Vậy S={+-10sqrt{29}}.
x^2 + 100 – 3000 = 0
⇔ x² – 2900 = 0
⇔ x² = 2900
⇔ x = $\sqrt{ 2900 }$
⇔ x = $\sqrt{ 29 . 100 }$
⇔ x = 10$\sqrt{29}$
Vậy x = 10$\sqrt{29}$