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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 4) $\frac{5x – 2}{4^2 y}$ + $\frac{x – 2}{4^2y}$ 5) $\frac{x + 4}{x^2 – 4}$ – $\frac{1}{x^2 + 2x}$ 6) $\frac{xy}{x^2 – y^2}$ – $\fr

Toán Lớp 8: 4) $\frac{5x – 2}{4^2 y}$ + $\frac{x – 2}{4^2y}$
5) $\frac{x + 4}{x^2 – 4}$ – $\frac{1}{x^2 + 2x}$
6) $\frac{xy}{x^2 – y^2}$ – $\frac{x^2}{y^2-x^2 }$

Comments ( 2 )

  1. Lời giải:
    4)
    (5x-2)/(4^(2)y)+(x-2)/(4^(2)y)     (y \ne 0)
    =(5x-2+x-2)/(4^(2)y)
    =(6x-4)/(4^(2)y)
    =[2(3x-2)]/(2.8y)
    =(3x-2)/(8y)
    5)
    (x+4)/(x^(2)-4)-1/(x^(2)+2x)       (x \ne ±2; x \ne 0)
    =[x(x+4)]/[x(x-2)(x+2)]-(x-2)/[x(x-2)(x+2)]
    =(x^(2)+4x-x+2)/[x(x-2)(x+2)]
    =(x^(2)+3x+2)/[x(x-2)(x+2)]
    =(x^(2)+x+2x+2)/[x(x-2)(x+2)]
    =[x(x+1)+2(x+1)]/[x(x-2)(x+2)]
    =[(x+1)(x+2)]/[x(x-2)(x+2)]
    =(x+1)/(x^(2)-2x)
    6)
    (xy)/(x^(2)-y^2)-(x^2)/(y^(2)-x^2)      (x \ne y)
    =(xy)/(x^(2)-y^2)+(x^2)/(x^(2)-y^2)
    =(xy+x^2)/(x^(2)-y^2)
    =[x.(y+x)]/[(x+y)(x-y)]
    =x/(x-y)

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     4) (5x-2)/(4^2 y) + (x-2)/(4^2 y) (y\ne0)
    =(5x-2+x-2)/(4^2 y)
    =(4x-4)/(4^2 y)
    =(4(x-1))/(4^2 y)
    =(x-1)/(4y)
    5) (x+4)/(x^2 -4) – 1/(x^2 +2x) (x\ne ±2 ; x\ne0)
    =(x(x+4))/(x(x-2)(x+2)) – (x-2)/(x(x-2)(x+2))
    =(x(x+4)-(x-2))/(x(x-2)(x+2))
    =(x^2 +4x-x+2)/(x(x-2)(x+2))
    =(x^2 +3x+2)/(x(x-2)(x+2))
    =(x^2 +x+2x+2)/(x(x-2)(x+2))
    =(x(x+1)+2(x+1))/(x(x-2)(x+2))
    =((x+1)(x+2))/(x(x-2)(x+2))
    =(x+1)/(x(x-2))
    =(x+1)/(x^2 -2x)
    6) (xy)/(x^2 -y^2) – (x^2)/(y^2 -x^2) (x\ney)
    =(xy)/(x^2 -y^2) + (x^2)/(x^2 -y^2)
    =(xy+x^2)/(x^2 -y^2)
    =(x(y+x))/((x-y)(x+y))
    =x/(x-y)

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222-9+11+12:2*14+14 = ? ( )

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