Toán Lớp 6: f) 47 – [(45.24– 52.12):14]
g) 50–[(20–23):2+34]
h)– 23 + 289 + 123 – 689.
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Toán Lớp 6: f) 47 – [(45.24– 52.12):14]
g) 50–[(20–23):2+34]
h)– 23 + 289 + 123 – 689.
Comments ( 2 )
Giải đáp:
$f) 47-[(45.24-52.12):14]$
$= 47-[(1080-624):14]$
$= 478-(456:14)$
$= 47-\dfrac{228}{7}$
$= \dfrac{101}{7}$
$g) 50-[(20-23):2+34]$
$= 50-[(-3):2+34]$
$= 50-[(-\dfrac{3}{2})+34]$
$= 50- 32,5$
$= 17,5$
$h) (-23)+289+123-689$
$= [(-23)+123]+(289-689)$
$= 100+(-400)$
$=-300$
f ) 47 – [(45 . 24 – 52 . 12) : 14]
= 47 – [(1080 – 624) : 14]
= 47 – [456 : 14]
= 47 – 228/7
= 101/7
g ) 50 – [(20 – 23) : 2 + 34]
= 50 – [(-3) : 2 + 34]
= 50 – [(-3)/2 + 34]
= 50 – 65/2
= 35/2
h ) -23 + 289 + 123 – 689
= [(-23) + 123] + (289 – 689)
= 100 + (-400)
= -300
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