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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x ∈ N biết: a) 3x ⋮ (x – 1) b) (2x + 7) ⋮ (x + 2)

Toán Lớp 6: Tìm x ∈ N biết:
a) 3x ⋮ (x – 1)
b) (2x + 7) ⋮ (x + 2)

Comments ( 2 )

  1. ta có 3x chia hết cho x-1
    => 3(x-1)+3 chia hết cho x-1
    => 3 chia hết cho x-1
    => x-1 ∈ Ư(3)
    => x-1∈ {1;3}
    => x ∈ {2;4}
    vậy x ∈ {2;4}
    b. ta có (2x+7) chia hết cho (x+2)
    => 2(x+2)+3 chia hết cho x+2
    => 3 chia hết cho x+2
    => x+2 ∈ Ư(3)
    x+2 ∈ {1;3} x ∈ {-1;1}
    mà x là số tự nhiên 
     x=1 
    vậy x=1
     

  2. a) 3x ⋮ (x – 1)
    → 3 . (x – 1) + 3 ⋮ (x – 1)
    Mà (x – 1) ⋮ cho (x – 1) nên 3 . (x – 1) ⋮ (x – 1)
    → 3 ⋮ (x – 1)
    Mà 3 ⋮ 1; 3.
    → x – 1 = 1; 3.
    → x = 2; 4.
    b) (2x + 7) ⋮ (x + 2)
    → 2 . (x + 2) + 3 ⋮ (x + 2)
    Mà (x + 2) ⋮ (x + 2) nên 2 . (x + 2) ⋮ (x + 2).
    → 3 ⋮ (x + 2)
    x + 2 ≥ 2.
    Mà 3 ⋮ 1; 3.
    → x + 2 = 3.
    → x = 1.

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222-9+11+12:2*14+14 = ? ( )

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