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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn `(x+3)/(x-2) + (x+2)/(3-x) + (x+2)/(x^2 – 5x+6)`

Toán Lớp 8: Rút gọn
(x+3)/(x-2) + (x+2)/(3-x) + (x+2)/(x^2 – 5x+6)

Comments ( 2 )

  1. #andy
    \[\begin{array}{l}
    \dfrac{{x + 3}}{{x – 2}} + \dfrac{{x + 2}}{{3 – x}} + \dfrac{{x + 2}}{{{x^2} – 5x + 6}}\\
     = \dfrac{{\left( {x + 3} \right)\left( {x – 3} \right)}}{{\left( {x – 2} \right)\left( {x – 3} \right)}} + \dfrac{{\left( {x + 2} \right)\left( {x – 2} \right)}}{{\left( {x – 2} \right)\left( {x – 3} \right)}} + \dfrac{{x + 2}}{{\left( {x – 2} \right)\left( {x – 3} \right)}}\\
     = \dfrac{{{x^2} – 9 – {x^2} + 4 + x + 2}}{{\left( {x – 2} \right)\left( {x – 3} \right)}}\\
     = \dfrac{{x – 3}}{{\left( {x – 2} \right)\left( {x – 3} \right)}}\\
     = \dfrac{1}{{x – 2}}
    \end{array}\]

  2. Giải đáp + Lời giải và giải thích chi tiết:
    Bạn tham khảo
    (x+3)/(x-2)+(x+2)/(2-x)+(x+2)/(x^2-5x+6)
    = (x+3)/(x-2)-(x+2)/(x-3)+(x+2)/(x^2-2x-3x+6)
    = (x+3)/(x-2)-(x+2)/(x-3)+(x+2)/(x(x-2)-3(x-2))
    = (x+3)/(x-2)-(x+2)/(x-3)+(x+2)/((x-2)(x-3))
    = ((x+3)(x-3)-(x+2)(x-2)+x+2)/((x-2)(x-3))
    = (x^2-9-x^2+4+x+2)/((x-2)(x-3))
    =(x-3)/((x-2)(x-3))
    =1/(x-2)

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222-9+11+12:2*14+14 = ? ( )