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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x, biết: a) x . ( x – 6 ) = 0 b) ( x + 3 ) . ( 2x – 14 ) = 0 c) ( x² – 225 ) . ( -4 – x ) = 0 d) x² – 2x = 0 e) x^5 – 81x = 0 g) 0

Home/ Toán Lớp 6: Tìm x, biết: a) x . ( x – 6 ) = 0 b) ( x + 3 ) . ( 2x – 14 ) = 0 c) ( x² – 225 ) . ( -4 – x ) = 0 d) x² – 2x = 0 e) x^5 – 81x = 0 g) 0

Toán Lớp 6: Tìm x, biết: a) x . ( x – 6 ) = 0 b) ( x + 3 ) . ( 2x – 14 ) = 0 c) ( x² – 225 ) . ( -4 – x ) = 0 d) x² – 2x = 0 e) x^5 – 81x = 0 g) 0

Tháng Chín 5, 2022 Toán học 2 Comments 0 views

Toán Lớp 6: Tìm x, biết:
a) x . ( x – 6 ) = 0
b) ( x + 3 ) . ( 2x – 14 ) = 0
c) ( x² – 225 ) . ( -4 – x ) = 0
d) x² – 2x = 0
e) x^5 – 81x = 0
g) 0 . x – 4 = 0
f) 0 . ( x – 5 ) = 0
h) ( x + 3 )² – 4 . ( x + 3 ) = 0
k) ( x + 7 )³ = 8x ³

Comments ( 2 )

  1. doanthulan
    doanthulan
    5 Tháng Chín, 2022 at 4:01 chiều
    Reply
    a) x . ( x – 6 ) = 0
    => \(\left[ \begin{array}{l}x=0\\x-6 = 0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x=0+6\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\) 
    Vậy x = 0 hoặc x = 6
    b) ( x + 3 ) . ( 2x – 14 ) = 0
    => \(\left[ \begin{array}{l}x+3=0\\2x-14=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0-3\\2x=0+14\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=-3\\x=7\end{array} \right.\) 
    Vậy x = -3 hoặc x = 7
    c) ( x² – 225 ) . ( -4 – x ) = 0
    => \(\left[ \begin{array}{l}x^2-225=0\\-4-x=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x^2=225\\x=-4\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=15\\x=-4\end{array} \right.\) 
    Vậy x = 15 hoặc x = -4
    d) x² – 2x = 0
    => x² = 0 và 2x = 0
    => x = 0 và x = 0
    Vậy x = 0
    e) x^5 – 81x = 0
    => x^5 = 0 và 81x = 0
    => x = 0 và x = 0
    Vậy x = 0
    g) 0 . x – 4 = 0
    f) 0 . ( x – 5 ) = 0
    => x – 5 = 0 : 0
    => x – 5 = 0
    => x = 0 + 5
    => x = 5
    Vậy x = 5
    h) ( x + 3 )² – 4 . ( x + 3 ) = 0
    => ( x + 3 )² = 0 và 4 . ( x + 3 ) = 0
    => x = -3 và x = -3
    Vậy x = -3
    k) ( x + 7 )³ = 8x ³
    => x + 7 = 8x
    => 8x – x = 7
    => 7x = 7
    => x = 7 : 7
    => x = 1
    Vậy x = 1

  2. annhocbichchaubich
    annhocbichchaubich
    5 Tháng Chín, 2022 at 4:01 chiều
    Reply
    a,x(x-6)=0
    ⇔\(\left[ \begin{array}{l}x=0\\x-6=0\end{array} \right.\) 
    ⇔\(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\) 
    Vậy…
    b,(x+3)(2x-14)=0
    ⇔(x+3)2(x-7)=0
    ⇔(x+3)(x-7)=0
    ⇔\(\left[ \begin{array}{l}x+3=0\\x-7=0\end{array} \right.\) 
    ⇔\(\left[ \begin{array}{l}x=-3\\x=7\end{array} \right.\) 
    Vậy…
    c,(x^2-225)(-4-x)=0
    ⇔\(\left[ \begin{array}{l}x^2-225=0\\-4-x=0\end{array} \right.\)
    ⇔ \(\left[ \begin{array}{l}x^2=225\\x=-4\end{array} \right.\)
    ⇔\(\left[ \begin{array}{l}x^2=15^2(=)\\x=-4\end{array} \right.\) \(\left[ \begin{array}{l}x=15\\x=-15\end{array} \right.\) 
    Vậy…
    d,x^2-2x=0
    ⇔x(x-2)=0
    ⇔\(\left[ \begin{array}{l}x=0\\x-2=0\end{array} \right.\) 
    ⇔\(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\) 
    Vậy…
    e,x^5-81x=0
    ⇔x(x^4-81)=0
    ⇔\(\left[ \begin{array}{l}x=0\\x^4=81\end{array} \right.\) 
    ⇔x=0;3;-3
    Vậy…

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222-9+11+12:2*14+14 = ? ( )

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