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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: $\sqrt[3]{8}$ `-` $\sqrt[3]{27}$ = ? Giúp với ạ

Toán Lớp 9: $\sqrt[3]{8}$ – $\sqrt[3]{27}$ = ?
Giúp với ạ

Comments ( 2 )

  1. $Đáp$ $án:$
    $=$ $-1$
    $Giải$ $thích$ $các$ $bước$ $giải:$
    $\sqrt[3]{8}$ -$\sqrt[3]{27}$
    $=$ $\sqrt[3]{2^{2}}$ -$\sqrt[3]{3^{2}}$ 
    $=$ $2-3$
    $=$ $-1$

  2.     $\sqrt[3]{8}$ – $\sqrt[3]{27}$
    = $\sqrt[3]{ ( 2 )³ }$ – $\sqrt[3]{ ( 3 )³ }$
    = 2 – 3
    = -1
     Vậy rút gọn biểu thức bằng -1

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222-9+11+12:2*14+14 = ? ( )