Toán Lớp 8: P = $\dfrac{2x² – 1}{x² + x}$ – $\dfrac{x – 1}{x}$ + $\dfrac{3}{x + 1}$
Tìm đkxđ của P
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Toán Lớp 8: P = $\dfrac{2x² – 1}{x² + x}$ – $\dfrac{x – 1}{x}$ + $\dfrac{3}{x + 1}$
Tìm đkxđ của P
Comments ( 2 )
P= $\dfrac{2x²−1}{x²+x}$ – $\dfrac{x−1}{x}$ + $\dfrac{3}{x+1}$
= $\dfrac{2x²−1}{x(x+1)}$ – $\dfrac{x−1}{x}$ + $\dfrac{3}{x+1}$
ĐKXĐ của P ⇒$\begin{cases} x$\ne$0\\x+1$\ne$0 ⇒ $\begin{cases} x$\ne$0\\x$\ne$-1