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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: chứng minh a=1/2 mũ 2 + 1/3 mũ 2+…+1/100 mũ 2 bé hơn 1

Toán Lớp 6: chứng minh a=1/2 mũ 2 + 1/3 mũ 2+…+1/100 mũ 2 bé hơn 1

Comments ( 2 )

  1. A = 1/(2^2) + 1/(3^2) + … + 1/(100^2)
    Có:
    1/(2^2) < 1/(1.2)
    1/(3^2) < 1/(2.3)
    ….
    1/(100^2) < 1/(99.100)
    => A < 1/(1.2) + 1/(2.3) + … + 1/(99.100)
    => A < 1/1 – 1/2 + 1/2 – 1/3 + … + 1/99 – 1/100
    => A < 1/1 – 1/100
    => A < 99/100
    Mà 99/100 < 1
    => A < 1
    Vậy A < 1

  2. Lời giải chi tiết:
    A=1/2^2+1/3^2+…+1/100^2
    Ta có:
    1/2^2<1/(1.2)
    1/3^2<1/(2.3)
    1/100^2<1/(99.100)
    =>1/2^2+1/3^2+…+1/100^2<1/(1.2)+1/(2.3)+…+1/(99.100)
    Hay A<1-1/2+1/2-1/3+…+1/99-1/100
    =>A<1-1/100<1
    Vậy A<1

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222-9+11+12:2*14+14 = ? ( )

About Thúy Mai