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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: `(1,5) . 11/6 + (4,5) . 11/6 – 2021^0` `(1/2)^2 + |-5/4| -` `\sqrt{36}/15` Cho hàm số y = f(x) = x + 2. Giá trị của x khi f(x) = 3 là

Toán Lớp 7: (1,5) . 11/6 + (4,5) . 11/6 – 2021^0
(1/2)^2 + |-5/4| – \sqrt{36}/15
Cho hàm số y = f(x) = x + 2. Giá trị của x khi f(x) = 3 là gì?

Comments ( 2 )

  1. _(1,5).11/6+(4,5).11/6-2021^0
    =11/6 . (1,5+4,5)-1
    =11/6 . 6 – 1
    =11-1
    =10
    _(1/2)^2+|-5/4|-$\dfrac{\sqrt{36}}{15}$ 
    =1/4+5/4-6/15
    =3/2-6/15
    =11/10

  2. a,
    1,5 . 11/6+4,5 . 11/6-2021^0
    =3/2 . 11/6+9/2 . 11/6-1
    =11/6.(3/2+9/2)-1
    =11/6.((3+9)/2)-1
    =11/6. 12/2-1
    =11/6 . 6-1
    =(11.6)/6
    =66/6-1
    =11-1
    =10
    b,
    (1/2)^2+|-5/4|-(\sqrt{36})/15
    =1^2/2^2+5/4-(\sqrt{6^2})/15
    =1/4+5/4-(|6|)/15
    =1/4+5/4-6/15
    =1/4+5/4-2/5
    =(1+5)/4-2/5
    =6/4-2/5
    =3/2-2/5
    =15/10-4/10
    =(15-4)/10
    =11/10
    c,
    Cho hàm số y=f(x)=x+2
    Khi f(x)=3 
    Ta có:
    x+2=3
    <=>x=3-2
    <=>x=1
    Vậy x=1 khi f(x)=3
     

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222-9+11+12:2*14+14 = ? ( )