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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x :Tìm x : a) 3x(x-2)+4(2-x)=0 b) 4x(x-3)-2(x-3)=0 c)2x(x-4)-x+4=0 Giúp với ạ hứa vote 5*

Tháng Mười 10, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Tìm x :Tìm x :
a) 3x(x-2)+4(2-x)=0
b) 4x(x-3)-2(x-3)=0
c)2x(x-4)-x+4=0
Giúp với ạ hứa vote 5*

Comments ( 2 )

  1. thudan
    thudan
    10 Tháng Mười, 2022 at 5:02 sáng
    Reply
    Giải đáp:
    a) x = 2 hoặc x = 4/3
    b) x = 3 hoặc x = 1/2
    c) x = 4 hoặc x = 1/2
    Lời giải và giải thích chi tiết:
    a)
    3x(x – 2) + 4(2 – x) = 0
    3x(x – 2) – 4(x – 2) = 0
    (x – 2)(3x – 4) = 0
    => \(\left[ \begin{array}{l}x-2=0\\3x – 4 = 0\end{array} \right.\)
    => \(\left[ \begin{array}{l}x= 2\\x = \dfrac{4}{3} \end{array} \right.\) 
    Vậy x = 2 hoặc x = 4/3
    _____________________________________
    b)
    4x(x – 3) – 2(x – 3) = 0
    (x – 3)(4x – 2) = 0
    2(x – 3)(2x – 1) = 0
    => \(\left[ \begin{array}{l}x-3=0\\2x – 1 = 0\end{array} \right.\)
    => \(\left[ \begin{array}{l}x= 3\\x = \dfrac{1}{2} \end{array} \right.\) 
    Vậy x = 3 hoặc x = 1/2
    _____________________________________
    c)
    2x(x – 4) – x + 4 = 0
    2x(x – 4) – (x – 4) = 0
    (x – 4)(2x – 1) = 0
    => \(\left[ \begin{array}{l}x-4=0\\2x – 1 = 0\end{array} \right.\)
    => \(\left[ \begin{array}{l}x= 4\\x = \dfrac{1}{2} \end{array} \right.\) 
    Vậy x = 4 hoặc x = 1/2
    #SunHee

  2. catlantuong
    catlantuong
    10 Tháng Mười, 2022 at 5:02 sáng
    Reply
    a)
    3x.(x-2)+4.(2-x)=0
    =>3x.(x-2)-4.(x-2)=0
    =>(x-2).(3x-4)=0
    =>\(\left[ \begin{array}{l}x-2=0\\3x-4=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=2\\3x=4\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=2\\x=\dfrac{4}{3}\end{array} \right.\) 
    Vậy x=2; x=\frac{4}{3}
    $\\$
    b)
    4x.(x-3)-2.(x-3)=0
    =>(x-3).(4x-2)=0
    =>\(\left[ \begin{array}{l}x-3=0\\4x-2=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=3\\4x=2\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=3\\x=\dfrac{2}{4}\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{2}\end{array} \right.\) 
    Vậy x=3; x=\frac{1}{2}
    $\\$
    c)
    2x.(x-4)-x+4=0
    =>2x.(x-4)-(x-4)=0
    =>(x-4).(2x-1)=0
    =>\(\left[ \begin{array}{l}x-4=0\\2x-1=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=4\\2x=1\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=4\\x=\dfrac{1}{2}\end{array} \right.\) 
    Vậy x=4; x=\frac{1}{2}
     

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222-9+11+12:2*14+14 = ? ( )

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