Toán Lớp 8: 2x/x+3 : 8xy/x^2 + 3x
giải giúp mk vs
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Toán Lớp 8: 2x/x+3 : 8xy/x^2 + 3x
giải giúp mk vs
Comments ( 2 )
Giải đáp:
$\dfrac{2x}{x+3}:\dfrac{8xy}{x^2+3x}$
$= \dfrac{2x.x.(x+3)}{(x+3).8xy}$
$= \dfrac{2x²}{8xy}$
$= \dfrac{x}{4y}$
$\frac{2x}{x+3}$ : $\frac{8xy}{x^{2}+3x}$
= $\frac{2x}{x+3}$ .$\frac{x.(x+3 )}{8xy}$
= $\frac{2x.x}{8xy}$
= $\frac{x}{4y}$
@Hạ
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