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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 3x(x-3)+7x-21=0 (2x+3)(3x-4)-6x(x+5)=1

Toán Lớp 8: 3x(x-3)+7x-21=0
(2x+3)(3x-4)-6x(x+5)=1

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
    ${3x(x-3)+7x-21=0}$
    ⇔${3x(x-3)+7(x-3)=0}$
    ⇔${(x-3)(3x+7)=0}$
    ⇔\(\left[ \begin{array}{l}x-3=0\\3x+7=0\end{array} \right.\)⇔ \(\left[ \begin{array}{l}x=3\\3x=-7\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=3\\x=\frac{-7}{3} \end{array} \right.\)
    ${b) (2x+3)(3x-4)-6x(x+5)=1}$
    ⇔${6x^2-8x+9x-12-6x^2-30x=1}$
    ⇔${-29x-12=1}$
    ⇔${-29x=1+12}$
    ⇔${-29x=13}$
    ⇔${x=}$ $\frac{-13}{29}$ 

  2. Giải đáp:
    a) \(\left[ \begin{array}{l}x=\dfrac{-7}{3}\\x=3\end{array} \right.\) 
    b) $x = \dfrac{-13}{29}$
    Lời giải và giải thích chi tiết:
     a) $3x(x – 3) + 7x – 21 = 0$
    $\Leftrightarrow 3x(x – 3) + 7(x – 3) = 0$
    $\Leftrightarrow (3x + 7)(x – 3) = 0$
    $\Leftrightarrow$\(\left[ \begin{array}{l}3x+7=0\\x-3=0\end{array} \right.\) 
    $\Leftrightarrow$\(\left[ \begin{array}{l}3x=-7\\x=3\end{array} \right.\) 
    $\Leftrightarrow$\(\left[ \begin{array}{l}x=\dfrac{-7}{3}\\x=3\end{array} \right.\) 
    b) $(2x + 3)(3x – 4) – 6x(x + 5) = 1$
    $\Leftrightarrow 6x^2 + 9x – 8x – 12 – (6x^2 + 30x) = 1$
    $\Leftrightarrow 6x^2 + x – 12 – 6x^2 – 30x = 1$
    $\Leftrightarrow -29x – 12 = 1$
    $\Leftrightarrow -29x = 1 + 12$
    $\Leftrightarrow -29x = 13$
    $\Leftrightarrow x = \dfrac{-13}{29}$

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222-9+11+12:2*14+14 = ? ( )