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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Chứng tỏ rằng A=2+2^2+2^3+-…+2^100 chia hết cho 6

Toán Lớp 6: Chứng tỏ rằng A=2+2^2+2^3+…….+2^100 chia hết cho 6

Comments ( 2 )

  1. $\text{A}$=$2^{}$+$2^{2}$+$2^{3}$+…+$2^{100}$
    $\text{A}$=($2^{}$+$2^{2}$)+$2^{3}$+$2^{4}$)+…+($2^{99}$+$2^{100}$)
    $\text{A}$=($2^{}$+$2^{2}$)+$2^{2}$($2^{}$+$2^{2}$)+…($2^{98}$($2^{}$+$2^{2}$) $\text{A}$=$6^{}$($1^{}$+$2^{2}$+…+$2^{98}$)
    $\text{Vậy}$ $\text{A}$ $\vdots$ $6^{}$

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222-9+11+12:2*14+14 = ? ( )