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222-9+11+12:2*14+14 = ? ( )

Hóa học Lớp 9: mn ơi giúp mik vs ạ,mik đang cần gấp:Hoàn thành dãy chuyển hóa sau Al–>Al2(SO4)3–>AlCL3–>Al(OH)3–>Al2O3–>Al2(CO3)3–>Al–>Al2O3

Hóa học Lớp 9: mn ơi giúp mik vs ạ,mik đang cần gấp:Hoàn thành dãy chuyển hóa sau
Al–>Al2(SO4)3–>AlCL3–>Al(OH)3–>Al2O3–>Al2(CO3)3–>Al–>Al2O3, giúp em giải bài hóa này ạ, em cảm ơn thầy cô và các bạn nhiều.

Comments ( 2 )

  1. Bạn tham khảo!
    Đề)
    $\text{Al$\xrightarrow{1}$Al2(SO4)3$\xrightarrow{2}$AlCl3$\xrightarrow{3}$Al(OH)3$\xrightarrow{4}$Al2O3$\xrightarrow{5}$Al2(CO3)3$\xrightarrow{6}$Al$\xrightarrow{7}$Al2O3}$
    Bài làm)
    $1)$ $2Al$ $+$ $3H_2(SO_4)_3$ $\rightarrow$ $Al_2(SO_4)_3$ $+$ $3H_2$
    $2)$ $Al_2(SO_4)_3$ $+$ $3BaCl_2$ $\rightarrow$ $3BaSO_4$ $+$ $2AlCl_3$
    $3)$ $AlCl_3$ $+$ $3NaOH$ $\rightarrow$ $3NaCl$ $+$ $Al(OH)_3$ 
    $4)$ $2Al(OH)_3$ $\xrightarrow{t^o}$ $Al_2O_3$ $+$ $3H_2O$
    $5)$ $Al_2O_3$ $+$ $3H_2CO_3$ $\rightarrow$ $Al_2(CO_3)_3$ $+$ $3H_2O$
    $6)$ $Al_2(CO_3)_3$ $+$ $3Mg$ $\rightarrow$ $3MgCO_3$ $+$ 2$Al$
    $7)$ $4Al$ $+$ $3O_2$ $\xrightarrow{t^o}$ $2Al_2O_3$
     

  2. – 2Al+3H_2SO_4→Al_2(SO_4)_3+3H_2
    – Al_2(SO_4)_3+3BaCl_2→3BaSO_4↓+2AlCl_3
    – AlCl_3+3NaOH→Al(OH)_3+3NaCl
    – 2Al(OH)_3 $\xrightarrow[]{t^o}$ Al_2O_3+3H_2O
    – Al_2O_3+3CO_2→Al_2(CO_3)_3
    – 3Mg+Al_2(CO_3)_3 $\xrightarrow[]{t^o}$ 3MgCO_3+2Al

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222-9+11+12:2*14+14 = ? ( )