Toán Lớp 8: (6x^3-5x^2+4x-1):(2x^2-x+1) (x^4-5x^2+4):(x^2-3x+2) (x^3-2x^2-5x+6):(x+2) -

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Toán Lớp 8: (6x^3-5x^2+4x-1):(2x^2-x+1) (x^4-5x^2+4):(x^2-3x+2) (x^3-2x^2-5x+6):(x+2)

Bích Hải Tháng Hai 2, 2023 Toán học 1 Comment 0 views

Toán Lớp 8: (6x^3-5x^2+4x-1):(2x^2-x+1)
(x^4-5x^2+4):(x^2-3x+2)
(x^3-2x^2-5x+6):(x+2)

Comments ( 1 )

doanthulan
2 Tháng Hai, 2023 at 3:09 sáng

Reply

Giải đáp:

(6x^3-5x^2+4x-1):(2x^2-x+1)

=(6x^3-3x^2+3x-2x^2+x-1):(2x^2-x+1)

=[3x(2x^2-x+1)-(2x^2-x+1)]:(2x^2-x+1)

=[(2x^2-x+1)(3x-1)]:(2x^2-x+1)

=3x-1

(x^4-5x^2+4):(x^2-3x+2)

=(x^4-3x^3+2x^2+3x^3-9x^2+6x+2x^2-6x+4):(x^2-3x+2)

=[x^2(x^2-3x+2)+3x(x^2-3x+2)+2(x^2-3x+2)]:(x^2-3x+2)

=[(x^2-3x+2)(x^2+3x+2)]:(x^2-3x+2)

=x^2+3x+2

(x^3-2x^2-5x+6):(x+2)

=(x^3+2x^2-4x^2-8x+3x+6):(x+2)

=[x^2(x+2)-4x(x+2)+3(x+2)]:(x+2)

=[(x+2)(x^2-4x+3)]:(x+2)

=x^2-4x+3.

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