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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 5: 1.Thực hiện phép tính: a) (5/7 : 3/4) x 2/5 + 131313/212121 b) (1 + 1/15) x (1 + 1/24) x (1 + 1/35) x…x (1 + 1/9999) 2.Tìm y, bi

Toán Lớp 5: 1.Thực hiện phép tính:
a) (5/7 : 3/4) x 2/5 + 131313/212121
b) (1 + 1/15) x (1 + 1/24) x (1 + 1/35) x…x (1 + 1/9999)
2.Tìm y, biết:
a) y x 3 – y x 7/5= 11,2
b) 1/3×5 + 1/5×7 + 1/7×9 +…+ 1/y x (y + 2)= 16/99 (y là số tự nhiên)

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    Câu 1:
    a)
    (5/7 : 3/4) . 2/5 + 131313/212121
    -> (5/7 : 3/4) . 2/5 + 13/21
    -> 20/21 . 2/5 + 13/21
    -> 8/21 + 13/21
    -> 1
    b) (1 + 1/15). (1 + 1/24) . (1 + 1/35) . …. . (1 + 1/9999)
    -> 16/15 . 25/24 . 36/35 . … . 10000/9999
    -> frac{16 . 25 . 36 . … . 10000}{15 . 24 . 35 . … . 9999}
    -> frac{4 . 4 . 5 . 5 . 6 . 6 . … . 100 . 100}{3 . 5 . 4 . 6 . 5 . 7 . … . 99 . 101}
    -> frac{4 . 100}{3 . 4 . 101}
    -> frac{100}{3 . 101}
    -> frac{100}{303}
    Câu 2:
    a) y . 3 – y . 7/5 = 11,2
    -> y . (3 – 7/5) = 11,2
    -> y . 1,6 = 11,2
    -> y= 11,2 : 1,6
    -> y = 7
    b) frac{1}{3 . 5} + frac{1}{5 . 7} + frac{1}{7 . 9} + … + frac{1}{y . (y + 2)} = 16/99
    -> 2 . frac{1}{3 . 5} + frac{1}{5 . 7} + frac{1}{7 . 9} + … + frac{1}{y . (y + 2)} = 16/99
    -> frac{2}{3 . 5} + frac{2}{5 . 7} + frac{2}{7 . 9} + … + frac{2}{y . (y + 2)} = 16/99 . 2
    -> frac{2}{3 . 5} + frac{2}{5 . 7} + frac{2}{7 . 9} + … + frac{2}{y . (y + 2)} = 32/99
    -> 1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + ….. + 1/y – frac{1}{y + 2} = 32/99
    -> frac{1}{3} – frac{1}{y + 2} = 32/99
    -> frac{1}{y + 2} = frac{1}{99}
    -> y + 2 = 99
    -> y = 97

  2. Câu 1
    a ) ( 5/7 : 3/4 ) × 2/5 + 131313/212121
    = 20/21 × 2/5 + 13/21
    = 8/21 + 13/21
    = 1
    b ) ( 1 + 1/15 ) × ( 1 + 1/24 ) × ( 1 + 1/35 ) × … × ( 1 + 1/9999 )
    = 16/15 × 25/24 × 36/35 × … × 10000/9999
    = {16 × 25 × 36 × … × 10000}/{15 × 24 × 35 × … × 9999}
    = {4 × 4 × 5 × 5 × 6 × 6 × … × 100 × 100}/{3 × 5 × 4 × 6 × 5 × 7 × … × 99 × 101}
    = {4 × 100}/{3 × 4 × 101}
    = 100/303
    Câu 2
    a ) y × 3 – y × 7/5 = 11,2
    y × ( 3 – 7/5 ) = 11,2
    y × 1,6 = 11,2
             y = 11,2 : 1,6
             y = 7
    b ) 1/{3 × 5} + 1/{5 × 7} + 1/{7 × 9} + … + 1/{y × ( y + 2 ) = 16/99}
    2 × ( 1/{3 × 5} + 1/{5 × 7} + 1/{7 × 9} + … + 1/{y × ( y + 2 )) = 16/99 × 2}
    2/{3 × 5} + 2/{5 × 7} + 2/{7 × 9} + … + 2/{y × ( y + 2 ) = 32/99
    1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + … + 1/y – 1/{y + 2} = 32/99
    1/3 – 1/{y + 2} = 32/99
    1/{y + 2} = 1/3 – 32/99
    1/{y + 2} = 1/99
    => y + 2 = 99
    => y = 99 – 2 = 97
    #dtkc

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222-9+11+12:2*14+14 = ? ( )