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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: `(x-2/9)^3=(2/3)^6` `(2/3.x-4/9)(1/2+(-3)/7:x)=0`

Tháng Một 19, 2023 Toán học 2 Comments 0 views

Toán Lớp 7: (x-2/9)^3=(2/3)^6
(2/3.x-4/9)(1/2+(-3)/7:x)=0

Comments ( 2 )

  1. minhtuyethue
    minhtuyethue
    19 Tháng Một, 2023 at 9:31 sáng
    Reply
    (x-2/9)^3 = (2/3)^6
    => (x-2/9)^3 = [(2/3)^2]^3
    => (x-2/9)^3 =(4/9)^3
    => x- 2/9 = 4/9
    => x = 4/9 + 2/9
    => x = 2/3
    Vậy x=2/3
    (2/3x – 4/9)(1/2 + (-3)/7 : x) = 0
    => 2/3x – 4/9 = 0 hoặc 1/2 + (-3)/7 : x = 0
    +) 2/3x – 4/9 = 0
    => 2/3x = 4/9
    => x = 2/3
    +) 1/2 + (-3)/7 : x = 0
    => (-3)/7 : x = -1/2
    => x = (-3)/7 : (-1)/2
    => x = 6/7
    Vậy x \in {2/3 ; 6/7}

  2. danvanthu
    danvanthu
    19 Tháng Một, 2023 at 9:31 sáng
    Reply
    a) (x-2/9)^3 = (2/3)^6
    (x-2/9)^3 = [(2/3)^2]^3
    (x-2/9)^3 = (4/9)^3
    ⇒ x – 2/9 = 4/9
    ⇒ x = 4/9 + 2/9
    ⇒ x = 2/3
    b) (2/3x – 4/9)(1/2 + -3/7 : x) = 0
    (2/3x – 4/9)(1/2 – 3/7x) = 0
    ⇒\(\left[ \begin{array}{l}\frac{2}{3}x – \frac{4}{9}=0\\1/2 – 3/7x = 0\end{array} \right.\)
    ⇒ \(\left[ \begin{array}{l}x=2/3\\x=6/7\end{array} \right.\) 

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222-9+11+12:2*14+14 = ? ( )

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