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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: x.y = 5/6, y.z = 7/6, x.z = 5/7

Toán Lớp 7: x.y = 5/6, y.z = 7/6, x.z = 5/7

Comments ( 2 )

  1. Ta có: x.y.y.z.z.x =5/6 . 7/6 . 5/7
    => x^2 y^2 z^2 = 25/36
    => (xyz)^2= 25/36
    +) (xyz )^2 = (5/6)^2
    => xyz = 5/6
    Mà xy = 5/6
    => z = 5/6 : 5/6 =1
    Với z =1 mà yz = 7/6 => y= 7/6 : 1 = 7/6
    Với z=1 mà x.z = 5/7 => x = 5/7 : 1 = 5/7
    +) (xyz)^2 = (-5/6)^2
    => xyz = -5/6
    Mà xy = 5/6
    => z = -5/6 : 5/6 = -1
    Với z=-1 mà yz = 7/6=> y = 7/6 : (-1) = -7/6
    Với z=-1 mà xz = 5/7 => x= 5/7:(-1) = -5/7
    Vậy x = 5/7 ; y= 7/6 ; z =1 hoặc x= -5/7 ; y= -7/6 ; z= -1

  2. $x.y=\dfrac{5}{6}⇔x=\dfrac{5}{6y}$
    $y.z=\dfrac{7}{6}⇔z=\dfrac{7}{6y}$
    $x.z=\dfrac{5}{7}$
    $⇔\dfrac{5}{6y}.\dfrac{7}{6y}=\dfrac{5}{7}$
    $⇔\dfrac{35}{36y^2}=\dfrac{5}{7}$
    $⇔245=180y^2$
    $⇔y^2=\dfrac{49}{36}$
    $⇔y=±\dfrac{7}{6}$
    Nếu $y=\dfrac{7}{6}⇒x=\dfrac{5}{6}:\dfrac{7}{6}=\dfrac{5}{7}$
    $z=\dfrac{7}{6}:\dfrac{7}{6}=1$
    $y=\dfrac{7}{6}⇒x=\dfrac{5}{6}:\dfrac{7}{6}=\dfrac{5}{7}$
    $z=\dfrac{7}{6}:\dfrac{7}{6}=1$
    Nếu$y=-\dfrac{7}{6}⇒x=\dfrac{5}{6}:(-\dfrac{7}{6})=-\dfrac{5}{7}$
    $z=\dfrac{7}{6}:(-\dfrac{7}{6})=-1$

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222-9+11+12:2*14+14 = ? ( )

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