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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Rút gọn biểu thức sau: ($3$-$\frac{\sqrt{2}+2}{\sqrt{2}+1}$ )($3$+$\frac{2-\sqrt{2}}{\sqrt{2}-1}$)

Toán Lớp 9: Rút gọn biểu thức sau:
($3$-$\frac{\sqrt{2}+2}{\sqrt{2}+1}$ )($3$+$\frac{2-\sqrt{2}}{\sqrt{2}-1}$)

Comments ( 2 )

  1. $\textit{Giải đáp + Lời giải và giải thích chi tiết:}$

    (3-(\sqrt{2}+2)/(\sqrt{2}+1))(3+(2-\sqrt{2})/(\sqrt{2}-1))

    =[3-(\sqrt{2}(\sqrt{2}+1))/(\sqrt{2}+1)][3+(\sqrt{2}(\sqrt{2}-1))/(\sqrt{2}-1)]

    =(3-\sqrt{2})(3+\sqrt{2})

    =3^2-(\sqrt{2})^2

    =7

     

  2. (3-(\sqrt{2}+2)/(\sqrt{2}+1)) . (3+(2-\sqrt{2})/(\sqrt{2}-1))

    =[(3(\sqrt{2}+1)-(\sqrt{2}+2))/(\sqrt{2}+1)] . [(3(\sqrt{2}-1)+2-\sqrt{2})/(\sqrt{2}-1)]

    =(3\sqrt{2}+3-\srt{2})/(\sqrt{2}+1) . (3\sqrt{2}-3+2-\sqrt{2})/(\sqrt{2}-1)

    =(2\sqrt{2}+1)/(\sqrt{2}+1) . (2\sqrt{2}-1)/(\sqrt{2}-1)

    =((2\sqrt{2}+1)(2\sqrt{2}-1))/((\sqrt{2}+1)(\sqrt{2}-1))

    =((2\sqrt{2})^2-1^2)/((\sqrt{2})^2-1^2)

    =(8-1)/(2-1)

    =7

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222-9+11+12:2*14+14 = ? ( )