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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Câu 1: Cho a+b+c=2p. CMR: a) a^2-b^2-c^2+2bc=4.(p-b).(p-c) b) p^2+(p-a)^2+(p-b)^2+(p-c)^2= a^2+b^2+c^2

Toán Lớp 8: Câu 1: Cho a+b+c=2p. CMR:
a) a^2-b^2-c^2+2bc=4.(p-b).(p-c)
b) p^2+(p-a)^2+(p-b)^2+(p-c)^2= a^2+b^2+c^2

Comments ( 2 )

  1. a) a^2 – b^2 – c^2 + 2bc
    = a^2 – (b^2 + c^2 – 2bc)
    = a^2 – (b – c)^2
    = (a – b + c)(a + b – c)
    = (2p – 2b)(2p – 2c)
    = 4(p-b)(p-c)
    => đpcm
    b) p^2+(p-a)^2+(p-b)^2+(p-c)^2= a^2+b^2+c^2
    = p^2 + (p^2 – 2ap + a^2) + (p^2 – 2bp + b^2) + (p^2 – 2cp + c^2)
    = 4p^2 + a^2 + b^2 + c^2 – 2p(a + b + c)
    = a^2 + b^2 + c^2 + 4p^2 – 2p.2p
    = a^2 + b^2 + c^2
    => đpcm

  2. Giải đáp + Lời giải và giải thích chi tiết:
    $a) a^2 – b^2 – c^2 + 2bc= a^2 – (b^2 + c^2 – 2bc)= a^2 – (b – c)^2$
    $= (a – b + c)(a + b – c)=(a+b+c-2b)(a+b+c-2c)$
    $=(2p-2b)(2p-2c)=4(p-b)(p-c)⇒ĐPCM$
    $b) p^2+(p-a)^2+(p-b)^2+(p-c)^2= a^2+b^2+c^2$
    $= p^2 + (p^2 – 2ap + a^2) + (p^2 – 2bp + b^2) + (p^2 – 2cp + c^2)$
    $= 4p^2 + a^2 + b^2 + c^2 – 2p(a + b + c)$
    $= a^2 + b^2 + c^2 + 4p^2 – 2p.2p= a^2 + b^2 + c^2$
    $⇒ĐPCM$
    Mk xin hay nhất ạ mk thật sự cần ạ 

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222-9+11+12:2*14+14 = ? ( )