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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (x+3)*(x^2-3x+9)-(54+x^3) (3x+4x^2)*(-x^2+1+2x) (2x-y)*(4x^2xy+y^2) mn giúp em vs ạ

Toán Lớp 8: (x+3)*(x^2-3x+9)-(54+x^3)
(3x+4x^2)*(-x^2+1+2x)
(2x-y)*(4x^2xy+y^2)
mn giúp em vs ạ

Comments ( 2 )

  1. Hướng dẫn trả lời:
    a) (x + 3)cdot(x^2 – 3x + 9) – (54 + x^3)
    = (x + 3)cdot(x^2 – xcdot3 + 3^2) – (54 + x^3)
    = (x^3 + 3^3) – (54 + x^3)
    = (x^3 + 27) – (54 + x^3)
    = x^3 + 27 – 54 – x^3
    = (x^3 – x^3) + (27 – 54)
    = – 27
    Giải thích:
    Áp dụng HĐT A^3 + B^3 = (A + B)cdot(A^2 – AB + B^2)
    b) (3x + 4x^2)cdot(-x^2 + 1 + 2x)
    = 3xcdot(-x^2 + 1 + 2x) + 4x^2cdot(-x^2 + 1 + 2x)
    = -3x^3 + 3x + 6x^2 – 4x^4 + 4x^2 + 8x^3
    = – 4x^4 + (- 3x^3 + 8x^3) + (6x^2 + 4x^2) + 3x
    = – 4x^4 + 5x^3 + 10x^2 + 3x
    c) (2x – y)cdot(4x^2xy + y^2)
    = (2x – y)cdot(4x^3y + y^2)
    = 2xcdot(4x^3y + y^2) – ycdot(4x^3y + y^2)
    = 8x^4y + 2xy^2 – 4x^3y^2 – y^3
    Giải đáp:
    a) = – 27 
    b) = – 4x^4 + 5x^3 + 10x^2 + 3x
    c) = 8x^4y + 2xy^2 – 4x^3y^2 – y^3

  2. Giải đáp+Lời giải và giải thích chi tiết:
    (x+3)*(x^2-3x+9)-(54+x^3)
    =(x^3+3^3)-(54+x^3)
    =x^3+27-54-x^3
    =(x^3-x^3)+(27-54)
    =-27
    (3x+4x^2)*(-x^2+1+2x)
    =3x(-x^2+2x+1)+4x^2(-x^2+1+2x)
    =-3x^3+6x^2+3x-4x^4+4x^2+8x^3
    =-4x^4+(8x^3-3x^3)+(6x^2+4x^2)+3x
    =-4x^4+5x^3+10x^2+3x
    (2x-y)*(4x^2xy+y^2)
    =(2x-y)(4x^3y+y^2)
    =2x(4x^3y+y^2)-y(4x^3y+y^2)
    =8x^4y+2xy^2-4x^3y^2-y^3
     

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222-9+11+12:2*14+14 = ? ( )

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