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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: (x) = x^3 (3x –1) – x (l + 3x^4); g(x) = x^2 (x^2 + 2) – x (–x^4 + 2x^2 +7) + 3; h(x) = x^3 (–2 + 2x – x^2) – (5x – 3 – 2x^2) a) Thu g

Toán Lớp 7: (x) = x^3 (3x –1) – x (l + 3x^4);
g(x) = x^2 (x^2 + 2) – x (–x^4 + 2x^2 +7) + 3;
h(x) = x^3 (–2 + 2x – x^2) – (5x – 3 – 2x^2)
a) Thu gọn rồi sắp xếp các hạng tử của mỗi đa thức trên theo lũy thừa giảm dần của biến.
b) Tính A(x) = (x) + g(x) – 2h(x).

Comments ( 2 )

  1. a,
    (x)=x³(3x-1)-x(1+3$x^{4}$ )
    =3$x^{4}$ -x³-x-3$x^{5}$ 
    =-3$x^{5}$+3$x^{4}$-x³-x;
    g(x)=$x^{4}$+2x²+$x^{5}$ -2x³-7x+3
    =$x^{5}$+$x^{4}$-2x³+2x²-7x+3
    h(x)=-2x³+2$x^{4}$ -$x^{5}$-5x+3+2x²
    =-$x^{5}$+2$x^{4}$-2x³+2x²-5x+3
    b,
            (x)= 3$x^{5}$+3$x^{4}$-  x³-           x
    +    g(x)=   $x^{5}$+  $x^{4}$-2x³+2x²- 7x+3
    –   2h(x)=-2$x^{5}$+4$x^{4}$-4x³+4x²-10x+6
    ————————————————
          A(x)= 6$x^{5}$+0              +x³-2x²+4x-3

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    ${a,}$
    ${(x) = x^3 (3x –1) – x (1 + 3x^4)}$
    ${(x)= 3x^4 – x^3 -x +3x^4}$
    ${(x)= 6x^4 – x^3 -x }$
    ${g(x) = x^2 (x^2 + 2) – x (–x^4 + 2x^2 +7) + 3}$
    ${g(x)=x^4 + 2x^2 + x^5 -2x^3 -7x +3}$
    ${g(x)= x^5 +x^4 -2x^3 + 2x^2 – 7x +3}$
    ${h(x) = x^3 (–2 + 2x – x^2) – (5x – 3 – 2x^2)}$
    ${h(x) = -2x^3 + 2x^4 -x^5 -5x +3+2x^2}$
    ${h(x) = -x^5 + 2x^4 -2x^3 +2x^2 – 5x + 3 }$
    ${b,}$
    ${A(x) = (x) + g(x) – 2h(x)}$
    ${A(x) = (6x^4 – x^3 -x) + (x^5 +x^4 -2x^3 + 2x^2 – 7x +3) – 2.(-x^5 + 2x^4 -2x^3 +2x^2 – 5x + 3)}$
    ${A(x) = (6x^4 – x^3 -x) + (x^5 +x^4 -2x^3 + 2x^2 – 7x +3) + 2x^5 – 4x^4 + 4x^3 – 4x^2 + 10x – 6}$
    ${A(x) = 6x^4 – x^3 -x + x^5 +x^4 -2x^3 + 2x^2 – 7x +3 + 2x^5 – 4x^4 + 4x^3 – 4x^2 + 10x – 6}$
    ${A(x) = 6x^4 – x^3 -x + x^5 +x^4 -2x^3 + 2x^2 – 7x +3 + 2x^5 – 4x^4 + 4x^3 – 4x^2 + 10x – 6}$
    ${A(x) =(x^5 + 2x^5) + (6x^4 + x^4- 4x^4) + (– x^3 -2x^3+ 4x^3) + (2x^2- 4x^2)+(-x- 7x + 10x) +(3- 6)}$
    ${A(x) = 3x^5 + 3x^4 + x^3 – 2x^2 + 2x – 3 }$

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222-9+11+12:2*14+14 = ? ( )

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