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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: rút gọn biểu thức: A = (a+b)^2+(b+c)^2+(c+a)^2 – 2(a^2+b^2+c^2) B = (x-5) ( x^2 – 5x+ 25 ) ( x^2 +5x+

Toán Lớp 8: rút gọn biểu thức: A = (a+b)^2+(b+c)^2+(c+a)^2 – 2(a^2+b^2+c^2)
B = (x-5) ( x^2 – 5x+ 25 ) ( x^2 +5x+25) (x+5) – 1000
GIÚP MÌNH VỚI Ạ !

Comments ( 2 )

  1. #Sad
    a)
    A= (a+b)^2+(b+c)^2+(c+a)^2-2(a^2+b^2+c^2)
    = a^2+2ab+b^2+b^2+2bc+c^2+c^2+2ac+a^2-2a^2-2b^2-2c^2
    = (a^2+a^2-2a^2)+(b^2+b^2-2b^2)+(c^2+c^2-2c^2)+2ab+2bc+2ac
    = 2ab+2bc+2ac
    \text{→Áp dụng:} (A+B)^2 = A^2+2AB+B^2
    b)
    B= (x-5)(x^2-5x+25)(x^2+5x+25)(x+5)-1000
    = [(x-5)(x^2+5x+25)][(x+5)(x^2-5x+25)]-1000
    = (x^3-125)(x^3+125)-1000
    = x^6-15625-1000
    = x^6-16625
    \text{→Áp dụng:}
    +) A^3+B^3 = (A+B)(A^2-AB+B^2)
    +) A^3-B^3 = (A-B)(A^2+AB+B^2)

  2. ***Lời giải***
    A = (a+b)^2+(b+c)^2+(c+a)^2 – 2(a^2+b^2+c^2)
    =a^2+2ab+b^2+b^2+2bc+c^2+c^2+2ac+a^2-2a^2-2b^2-2c^2
    =(a^2+a^2-2a^2)+(b^2+b^2-2b^2)+(c^2+c^2-2c^2)+2ab+2bc+2ac
    =2ab+2bc+2ac
    B = (x-5) ( x^2 – 5x+ 25 ) ( x^2 +5x+25) (x+5) – 1000
    =[(x-5) ( x^2 +5x+25)][ (x+5)( x^2 – 5x+ 25 )]  – 1000
    =(x^3-125)(x^3+125)  – 1000
    =x^6-15625- 1000
    =x^6+(-15625- 1000)
    =x^6-16625
    *Áp dụng: (A+B)^2=A^2+2AB+B^2
                     (A±B) ( A^2 ± AB+ B^2 )=A^3±B^3

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222-9+11+12:2*14+14 = ? ( )