Toán Lớp 7: $\frac{5}{7}$ -(2x – $\frac{3}{5}$ ) = √ $\frac{1}{49}$
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Toán Lớp 7: $\frac{5}{7}$ -(2x – $\frac{3}{5}$ ) = √ $\frac{1}{49}$
Comments ( 2 )
$\text{$\frac{5}{7}$ – ( 2x – $\frac{3}{5}$ ) = $\sqrt{\frac{1}{49}}$}$
$\text{$\frac{5}{7}$ – ( 2x – $\frac{3}{5}$ ) = $\frac{1}{7}$}$
$\text{( 2x – $\frac{3}{5}$ )= $\frac{5}{7}$- $\frac{1}{7}$}$
$\text{( 2x – $\frac{3}{5}$ )= $\frac{4}{7}$}$
$\text{2x – $\frac{3}{5}$ = $\frac{4}{7}$}$
$\text{2x =$\frac{4}{7}$ + $\frac{3}{5}$}$
$\text{2x =$\frac{41}{35}$
$\text{x = $\frac{41}{35}$ : 2}$
$\text{x = $\frac{41}{70}$}$
Giải đáp + Lời giải và giải thích chi tiết:
5/7 – (2x – 3/5) = √1/49
2x – 3/5 = 5/7 – 1/7
2x – 3/5 = 4/7
2x = 4/7 + 3/5
2x = 41/35
x = 41/35 : 2
x = 41/70