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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: 1Giúp mình với ạ Tìm GTLN ,GTNN y=3+√cos x 2Giải phương trình sin x=2/5 sin(x+30°) =sin (2x+55) cos(2x+1)=1 cos(x-2)=sin 3(x-n/2

Toán Lớp 11: 1Giúp mình với ạ Tìm GTLN ,GTNN
y=3+√cos x
2Giải phương trình
sin x=2/5
sin(x+30°) =sin (2x+55)
cos(2x+1)=1
cos(x-2)=sin 3(x-n/2

Comments ( 1 )

  1. 1.  Vì -1≤ cosx ≤ 1
      nên: 0 ≤ √cosx ≤ 1
         ⇔0+3 ≤ √cosx + 3 ≤1+3
         ⇔ 3≤ 3 + √cosx ≤ 4
          ⇔ 3≤ y≤ 4
    ymax = 4 ⇒ cosx = 1 ⇒ x = k2π ( k∈Z)
    ymin = 3 ⇒ cosx = 0 ⇒ x = π/2 + kπ ( k∈ Z)
    2.
      a) sinx = 2/5
    ⇔ x= arcsin( 2/5) + k2π
         x= π-arcsin(2/5) + k2π  ( k∈Z)
       b) sin(x+ 30° ) = sin ( 2x + 55°)
          ⇔ x+ 30°= 2x + 55° + k360°
               x+ 30°= 180°-(2x+55°) + k360°
          ⇔ x -2x = 55°-30° + k360°
               x+ 30 °= 180° -2x – 55° + k360°
          ⇔ -x = 25° + k360°
                x + 2x = 180°-55°-30° + k360°
          ⇔ x= -25° – k360°
              3x= 95° + k360° ( k ∈ Z)
       c) cos(2x+1)=1
        ⇔ 2x+1 = k2π
        ⇔ 2x= -1 + k2π
        ⇔ x = -1/2 + kπ ( k∈Z)
        d) cos(x-2)= sin3(x-π/2)
        ⇔ cos (x-2) = sin( 3x- 3π/2)
        ⇔ cos ( x-2) = cos [ π/2 -( 3x- 3π/2)]
        ⇔ cos (x-2) = cos ( -3x + 2π)
        ⇔ x-2 = -3x+2π + k2π
             x-2 = – ( -3x+2π) + k2π
        ⇔ x + 3x = 2 + 2π + k2π
             x-2 = 3x – 2π + k2π
        ⇔ 4x = 2 + 2π + k2π
           x-3x=  2 -2π + k2π
        ⇔ x = 1/2 + π/2 + kπ/2
            -2x= 2-2π+k2π
        ⇔ x = 1/2 + π/2 + kπ/2
             x= -1 + π – kπ ( k ∈ Z)
          
         
            
     

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222-9+11+12:2*14+14 = ? ( )