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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Bài 3: Rút gọn biểu thức: a) (a+1)^2-(a-1)^2-3(a+1)(a-1) b) (m^3-m+1)^2+(m^2-3)2-2(m^2-3)(m^3-m+1) Bài 4: Tìm x, biết: a) ( 5x +1)^2

Toán Lớp 8: Bài 3: Rút gọn biểu thức:
a) (a+1)^2-(a-1)^2-3(a+1)(a-1)
b) (m^3-m+1)^2+(m^2-3)2-2(m^2-3)(m^3-m+1)
Bài 4: Tìm x, biết:
a) ( 5x +1)^2 – ( 5x +3)( 5x – 3) = 3
b) (3x-5)(5-3x)+9(x+1)^2=30
c) (x+4)^2-(x+1)(x-1)=16

Comments ( 2 )

  1. B3: 
    a, $(a+1)^{2} – (a-1)^{2} – 3(a+1).(a-1)$
    = $a^{2} + 2a + 1 – a^{2} + 2a – 1 -3a^{2} + 3$
    = $-3a^{2}+4a +3$
    b, $(m^{3}-m+1)^{2}+(m^{2}-3)^{2}-2(m^{2}-3)(m^{3}-m+1)$
    = $(m^{3} – m + 1 – m^{2} + 3)^{2}$
    = $(m^{3} – m^{2} – m + 4)^{2}$
    B4: 
    a, $(5x +1)^{2} – (5x +3)(5x – 3) = 3$
    ⇔ $25x^{2} +10x + 1 – 25x^{2} + 9 =3$
    ⇔ $10x = -7$
    ⇔ $x = \frac{-7}{10}$ 
    b, $(3x-5)(5-3x)+9(x+1)^{2}=30$
    ⇔ $-9x^{2} +30x – 25 + 9x^{2} +18x + 9 = 30$
    ⇔ $48x = 46$
    ⇔ $x  = \frac{23}{24}$
    c, $(x+4)^{2}-(x+1)(x-1)=16$
    ⇔ $x^{2} + 8x + 16 – x^{2} + 1 = 16$
    ⇔ $8x = -1$
    ⇔ $x = \frac{-1}{8}$

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222-9+11+12:2*14+14 = ? ( )