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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x 49x²-1=0 Giúp mình làm với

Toán Lớp 8: Tìm x
49x²-1=0
Giúp mình làm với

Comments ( 2 )

  1. #tnvt
    49x^2-1=0
    <=>(7x)^2-1^2=0
    <=>(7x-1)(7x+1)=0
    <=>[(7x-1=0),(7x+1=0):}
    <=>$\left[\begin{matrix} x=\dfrac{1}{7} \\ x=\dfrac{-1}{7}\end{matrix}\right.$
    Vậy x\in{1/7;-1/7}
    Áp dụng HĐT: a^2-b^2=(a-b)(a+b)

  2. $49x^{2} $ – $1$ = $0$
    ⇔ $(7x)^{2}$ – $1$  = $0$
    ⇔ ( $7x$ – $1$ )( $7x$ + $1$) = $0$
    ⇔\(\left[ \begin{array}{l}7x-1=0\\7x+1=0\end{array} \right.\) 
    ⇔\(\left[ \begin{array}{l}\ x= \frac{1}{7} \\x=\frac{-1}{7} \end{array} \right.\) 
    Vậy …

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222-9+11+12:2*14+14 = ? ( )

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