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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Câu 142:`(3-`$\sqrt{10}$`)`$\sqrt{19+3\sqrt{40}}$

Toán Lớp 9: Câu 142:(3-$\sqrt{10}$)$\sqrt{19+3\sqrt{40}}$

Comments ( 2 )

  1. chúc bn hc tốt vote mk 5* và ctlhn  nhé
     

    toan-lop-9-cau-142-3-sqrt-10-sqrt-19-3-sqrt-40

  2. #tnvt
    (3-\sqrt{10})\sqrt{19+3\sqrt{40}}
    =(3-\sqrt{10})\sqrt{10+2.3.\sqrt{10}+9}
    =(3-\sqrt{10})\sqrt{(\sqrt{10}+3)^2}
    =(3-\sqrt{10})|\sqrt{10}+3|
    =(3-\sqrt{10})(\sqrt{10}+3)
    =3^2-\sqrt{10}^2
    =9-10
    =-1

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222-9+11+12:2*14+14 = ? ( )