Toán Lớp 9: Tìm m:
-\frac{m-1}{2m-3}>0
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Toán Lớp 9: Tìm m:
-\frac{m-1}{2m-3}>0
Comments ( 1 )
DK:m \ne \dfrac{3}{2}\\
– \dfrac{{m – 1}}{{2m – 3}} > 0\\
\to \dfrac{{m – 1}}{{2m – 3}} < 0\\
\to \left[ \begin{array}{l}
\left\{ \begin{array}{l}
m – 1 < 0\\
2m – 3 > 0
\end{array} \right.\\
\left\{ \begin{array}{l}
m – 1 > 0\\
2m – 3 < 0
\end{array} \right.
\end{array} \right.\\
\to \left[ \begin{array}{l}
\left\{ \begin{array}{l}
m < 1\\
m > \dfrac{3}{2}
\end{array} \right.\left( l \right)\\
\dfrac{3}{2} > m > 1
\end{array} \right.
\end{array}\)