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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: tìm GTLN a,-2x²+5x-15 c,C=-4x²-4x-7 d,D=-10-8x-16x² e,E=-3x²+12x-13

Toán Lớp 9: tìm GTLN
a,-2x²+5x-15
c,C=-4x²-4x-7
d,D=-10-8x-16x²
e,E=-3x²+12x-13

Comments ( 1 )

  1. a)A=-2x²+5x-15
           =-2(x²-5/2x+15/2)
           =-2(x²-5/2x+25/16+95/16)
           =-2(x²-5/2x+25/16)-95/8
           =-2[x²-2.x. 5/4+(5/4)^2]-95/8
           =-2(x-5/4)^2-95/8
    Ta có:(x-5/4)^2≥0∀x
    ⇒2(x-5/4)^2≥0∀x
    ⇒-2(x-5/4)^2≤0∀x
    ⇒-2(x-5/4)^2-95/8≤-95/8∀x
    Vậy A_(max)=-95/8 khi x-5/4=0⇔=5/4
    c)C=-4x²-4x-7
           =-4(x²+x+7/4)
           =-4(x²+x+1/4+3/2)
           =-4(x²+x+1/4)-6
           =-4[x²+2.x. 1/2+(1/2)^2]-6
           =-4(x+1/2)^2-6
    Ta có:(x+1/2)^2≥0∀x
    ⇒4(x+1/2)^2≥0∀x
    ⇒-4(x+1/2)^2≤0∀x
    ⇒-4(x+1/2)^2-6≤-6∀x
    Vậy C_(max)=-6 khi x+1/2=0⇔x=-1/2
    d)D=-10-8x-16x²
           =-(16x²+8x+10)
           =-(16x²+8x+1+9)
           =-(16x²+8x+1)-9
           =-[(4x)²+2.4x.1+1²]-9
           =-(4x+1)²-9
    Ta có:(4x-1)²≥0∀x
    ⇒-(4x-1)²≤0∀x
    ⇒-(4x-1)²-9≤-9∀x
    Vậy D_(max)=-9 khi 4x-1=0⇔x=1/4
    e)E=-3x²+12x-13
           =-3(x²-4x+13/3)
           =-3(x²-4x+4+1/3)
           =-3(x²-4x+4)-1
           =-3(x²-2.x.2+2²)-1
           =-3(x-2)²-1
    Ta có:(x-2)²≥0∀x
    ⇒3(x-2)²≥0∀x
    ⇒-3(x-2)²≤0∀x
    ⇒-3(x-2)²-1≤-1
    Ta có:(x-2)²≥0∀x
    ⇒3(x-2)²≥0∀x
    ⇒-3(x-2)²≤0∀x
    ⇒-3(x-2)²-1≤-1∀x
    Vậy E_(max)=-1 khi x-2=0⇔x=2
     

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222-9+11+12:2*14+14 = ? ( )

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