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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Tìm x: a/ √ $x^{2}$ =5 b/ √ $x^{2}$ = 2x-1

Toán Lớp 9: Tìm x:
a/ √ $x^{2}$ =5
b/ √ $x^{2}$ = 2x-1

Comments ( 2 )

  1. a)
    \sqrt{x^2}=5
    <=>x^2=25
    <=>\(\left[ \begin{array}{l}x=5\\x=-5\end{array} \right.\) 
    Vậy S={5;-5}
    b)
    \sqrt{x^2}=2x-1 (Điều kiện: x>=1/2)
    <=>x^2=4x^2-4x+1
    <=>x^2-4x^2+4x-1=0
    <=>-3x^2+4x-1=0
    <=>-3x^2+3x+x-1=0
    <=>-3x(x-1)+(x-1)=0
    <=>(x-1)(-3x+1)=0
    <=>\(\left[ \begin{array}{l}x-1=0\\-3x+1=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=1\ (\text{thỏa mãn điều kiện})\\x=\dfrac{1}{3}\ (\text{thỏa mãn điều kiện})\end{array} \right.\) 
    Vậy S={1}

  2. Giải đáp:
    a,căn x^2=5
    <==> x^2=25
    <==>x=5 hoặc x=-5
    b,căn x^2=2x-1
    <==>x^2=(2x-1)^2
    <==>x^2=4x^2 -4x+1
     <==>3x^2 -4x+1=0
    <==>x=1 hoặc x=1/3

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222-9+11+12:2*14+14 = ? ( )