Toán Lớp 9: Tìm x
√x – 3 + √4x – 12 – 1/3 . √9x – 27 = 3
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Toán Lớp 9: Tìm x
√x – 3 + √4x – 12 – 1/3 . √9x – 27 = 3
Comments ( 2 )
=>ĐK:x\geq3
=\sqrt[x-3]+2\sqrt[x-3]-1/3. 3\sqrt[x-3]=3
=\sqrt[x-3].(1+2-1)=3
=2\sqrt[x-3]=3
=\sqrt[x-3]=3:2
=\sqrt[x-3]=3/2
=x-3=9/4
=x=9/4+3
=>x=21/4