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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: So sánh $\sqrt{3}$ + 2 với $\sqrt{2}$ + $\sqrt{6}$

Toán Lớp 9: So sánh $\sqrt{3}$ + 2 với $\sqrt{2}$ + $\sqrt{6}$

Comments ( 2 )

  1. Ta có: (√3+2)^2=(√3)^2+2.√3.2+4=3+4.√3+4=7+4√3
    (√2+√6)^2=(√2)^2+2.√2.√6+(√6)^2=2+2√12+6=8+4√3
    do 7<8 ⇒7+4√3<8+4√3 ⇒√3+2<√2+√6
     

  2. #andy
    Ta có: (√3+2)^2=(√3)^2+2.√3.2+4=3+4.√3+4=7+4√3
    (√2+√6)^2=(√2)^2+2.√2.√6+(√6)^2=2+2√12+6=8+4√3
    do 7<8 ⇒7+4√3<8+4√3 ⇒√3+2<√2+√6

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222-9+11+12:2*14+14 = ? ( )