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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: rút gọn biểu thức `\sqrt{19+6\sqrt{2}}-\sqrt{19-6\sqrt{2}}`

Toán Lớp 9: rút gọn biểu thức
\sqrt{19+6\sqrt{2}}-\sqrt{19-6\sqrt{2}}

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
    \sqrt{19+6\sqrt{2}}-\sqrt{19-6\sqrt{2}}
    =\sqrt{18+1+6\sqrt{2}}-\sqrt{18+1-6\sqrt{2}}
    =\sqrt{(3\sqrt{2})^2+1+2.3\sqrt{2}}-\sqrt{(3\sqrt{2})^2+1-6\sqrt{2}}
    =\sqrt{(3\sqrt{2}+1)^2}-\sqrt{(3\sqrt{2}-1)^2}
    =|3\sqrt{2}+1|-|3\sqrt{2}-1|
    =3\sqrt{2}+1-3\sqrt{2}+1
    =2
     

  2. Đặt : $A=\sqrt[]{19+6\sqrt[]{2}}-\sqrt[]{19-6\sqrt[]{2}}>0$ 
    $=>A^2=19+6\sqrt[]{2}+19-6\sqrt[]{2}-2\sqrt[]{(19+6\sqrt[]{2})(19-6\sqrt[]{2})}$
    $=38-2\sqrt[]{19^2-(6\sqrt[]{2})^2}$
    $=38-2\sqrt[]{361-72}$
    $=38-2\sqrt[]{289}$
    $=38-2.17$
    $=38-34=4$
    $=>A =\sqrt[]{4}=2$ 
    Hay $\sqrt[]{19+6\sqrt[]{2}}-\sqrt[]{19-6\sqrt[]{2}}=2$ 
     

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222-9+11+12:2*14+14 = ? ( )