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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Rút gọn biểu thức a).√2+√8+√50 b).4√3+√27 c).√2x – √8x +4√18x (x>=0)

Toán Lớp 9: Rút gọn biểu thức
a).√2+√8+√50
b).4√3+√27
c).√2x – √8x +4√18x (x>=0)

Comments ( 2 )

  1. a. \sqrt{2} + \sqrt{8} + \sqrt{50}
    = \sqrt{2} + \sqrt{2^2 . 2} + \sqrt{5^2 . 2}
    = \sqrt{2} + 2\sqrt{2} + 5\sqrt{2}
    = 8\sqrt{2}
    b. 4\sqrt{3} + \sqrt{27}
    = 4\sqrt{3}  + \sqrt{3^2 . 3}
    = 4\sqrt{3}  + 3\sqrt{3}
    = 7\sqrt{3}
    c. \sqrt{2x} – \sqrt{8x} + 4\sqrt{18x}
    = \sqrt{2x} – \sqrt{2^2 . 2x} + 4\sqrt{3^2 . 2x}
    = \sqrt{2x} – 2\sqrt{2x} + 12\sqrt{2x}
    = 11\sqrt{2x}

  2. Giải đáp + Lời giải và giải thích chi tiết:
    a)
    \sqrt2+\sqrt8+\sqrt{50}
    =\sqrt2+\sqrt{2^2 .2}+\sqrt{5^2 .2}
    =\sqrt2+2\sqrt2+5\sqrt2
    =\sqrt2 .(1+2+5)
    =8\sqrt2
    b)
    4\sqrt3+\sqrt{27}
    =4\sqrt3+\sqrt{3^2 .3}
    =4\sqrt3+3\sqrt3
    =\sqrt3 .(4+3)
    =7\sqrt3
    c)
    \sqrt{2x}-\sqrt{8x}+4\sqrt{18x}(x\ge0)
    =\sqrt2.\sqrtx-\sqrt{2^2 .2.x}+4\sqrt{3^2 .2.x}
    =\sqrt2.\sqrtx-2.\sqrt2.\sqrtx+4.3.\sqrt2.\sqrtx
    =\sqrt2.\sqrtx(1-2+12)
    =11\sqrt{2x}

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222-9+11+12:2*14+14 = ? ( )