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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Rút gọn `B=1/( √ 3)+1/(3√2)+1/( √3) √(5/12-1/( √6)) `

Toán Lớp 9: Rút gọn
B=1/( √ 3)+1/(3√2)+1/( √3) √(5/12-1/( √6))

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    $\text{Bạn xem hình ạ}$
    $\text{CHÚC BẠN HỌC TỐT!!!}$
    $@Sherry2007$

    toan-lop-9-rut-gon-b-1-3-1-3-2-1-3-5-12-1-6

  2. @Mon
    B=\frac{1}{\sqrt{3}}+\frac{1}{3\sqrt{2}}+\frac{1}{\sqrt{3}}\sqrt{(\frac{5}{12})-\frac{1}{\sqrt{6})}
    =\frac{\sqrt{3}}{\sqrt{3}\sqrt{3}}+\frac{2}{3\sqrt{2}\sqrt{2}}+\frac{\sqrt{3}}{\sqrt{3}\sqrt{3}}\sqrt{\frac{5}{12}-\frac{\sqrt{6}}{\sqrt{6}\sqrt{6}}}
     =\frac{\sqrt{3}}{3}+\frac{\sqrt{2}}{6}+\frac{\sqrt{3}}{3}\sqrt{\frac{5}{12}-\frac{\sqrt{6}}{\sqrt{2}}}
    =\frac{\sqrt{3}}{3}(1+\sqrt{\frac{5}{12}-\frac{2\sqrt{6}}{12}})+\frac{\sqrt{2}}{6}
    =\frac{\sqrt{3}}{3}(1+\sqrt{\frac{5-2\sqrt{6}}{12}})+\frac{\sqrt{2}}{6}
    =\frac{\sqrt{3}}{3}(1+\sqrt{\frac{\sqrt{3^2}-2\sqrt{3}.\sqrt{2}+\sqrt{2^2}}{\sqrt{12}}})+\frac{\sqrt{2}}{6}
    =\frac{\sqrt{3}}{3}(1+\frac{(\sqrt{3}-\sqrt{2})^2}{\sqrt{12}})+\frac{\sqrt{2}}{6}
    =\frac{\sqrt{3}}{3}(\frac{\sqrt{12}+\sqrt{3}-\sqrt{2}}{\sqrt{12}})+\frac{\sqrt{2}}{6}
    =\frac{1}{6}(3\sqrt{3}-\sqrt{2})+\frac{\sqrt{2}}{6}
    =\frac{3\sqrt{3}-\sqrt{2}+\sqrt{2}}{6}
    =\frac{3\sqrt{3}}{6}
    =\frac{\sqrt{3}}{2}

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222-9+11+12:2*14+14 = ? ( )