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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Rút gọn a. $\frac{2\sqrt[]{2}-4 }{4-\sqrt[]{2}}$ b.$\frac{\sqrt[]{10}-\sqrt[]{2} }{\sqrt[]{5}-2}$+$\frac{2-\sqrt[]{2} }{1-\sqrt[]{2}}$

Home/ Toán Lớp 9: Rút gọn a. $\frac{2\sqrt[]{2}-4 }{4-\sqrt[]{2}}$ b.$\frac{\sqrt[]{10}-\sqrt[]{2} }{\sqrt[]{5}-2}$+$\frac{2-\sqrt[]{2} }{1-\sqrt[]{2}}$

Toán Lớp 9: Rút gọn a. $\frac{2\sqrt[]{2}-4 }{4-\sqrt[]{2}}$ b.$\frac{\sqrt[]{10}-\sqrt[]{2} }{\sqrt[]{5}-2}$+$\frac{2-\sqrt[]{2} }{1-\sqrt[]{2}}$

Tháng Tám 30, 2022 Toán học 2 Comments 0 views

Toán Lớp 9: Rút gọn
a. $\frac{2\sqrt[]{2}-4 }{4-\sqrt[]{2}}$
b.$\frac{\sqrt[]{10}-\sqrt[]{2} }{\sqrt[]{5}-2}$+$\frac{2-\sqrt[]{2} }{1-\sqrt[]{2}}$

Comments ( 2 )

  1. tuyetanhthu
    tuyetanhthu
    30 Tháng Tám, 2022 at 7:29 sáng
    Reply
    Giải đáp+Lời giải và giải thích chi tiết:
     a) \frac{2\sqrt{2} – 4}{4 – \sqrt{2}}
    = \frac{2\sqrt{2}(1 – \sqrt{2})}{\sqrt{2}(2\sqrt{2} – 1)}
    = \frac{2\sqrt{2}(1 – \sqrt{2})}{\sqrt{2}(\sqrt{2} – 1)(2 + \sqrt{2} + 1)}
    = \frac{-2}{3 + \sqrt{2}}
    = \frac{2(3 – \sqrt{2})}{7}
    = \frac{6 – 2\sqrt{2}}{7}
    b) \frac{\sqrt{10} – \sqrt{2}}{\sqrt{5} – 2} + \frac{2 – \sqrt{2}}{1 – \sqrt{2}}
    = \frac{(\sqrt{10} – \sqrt{2})(\sqrt{5} + 2)}{5 – 4} + \frac{\sqrt{2}(\sqrt{2} – 1)}{1 – \sqrt{2}}
    = \sqrt{50} + 2\sqrt{10} – \sqrt{10} – 2\sqrt{2} – \sqrt{2}
    = \sqrt{10} + 2\sqrt{2}

  2. baoquyen
    baoquyen
    30 Tháng Tám, 2022 at 7:28 sáng
    Reply
    #tnvt
    a)\frac{2\sqrt{2}-4}{4-\sqrt{2}}
    =\frac{(2\sqrt{2}-4)(4+\sqrt{2})}{16-2}
    =\frac{8\sqrt{2}+4-16-4\sqrt{2}}{14}
    =\frac{4\sqrt{2}-12}{14}
    =\frac{2\sqrt{2}-6}{7}
    b)\frac{\sqrt{10}-\sqrt{2}}{\sqrt{5}-2}+\frac{2-\sqrt{2}}{1-\sqrt{2}}
    =\frac{(\sqrt{10}-\sqrt{2})(\sqrt{5}+2)}{5-4}+\frac{\sqrt{2}(\sqrt{2}-1)}{1-\sqrt{2}}
    =\sqrt{50}+2\sqrt{10}-\sqrt{10}-2\sqrt{2}-\sqrt{2}
    =5\sqrt{2}+\sqrt{10}-3\sqrt{2}
    =2\sqrt{2}+\sqrt{10}

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222-9+11+12:2*14+14 = ? ( )

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